Math

Elementary Number Theory Problems 4.3 Solution (David M. Burton's 7th Edition) - Q2 Members Public

My solution for "Prove the following statements: (a) For any integer $a$, the units digit of $a^{2}$ is $0, 1, 4, 5, 6,$ or $9$. (b) Any one of the integers $0, 1, 2, 3, 4, 5, 6, 7, 8, 9$ can occur as the units digit of $a^{3}$. (c) For any integer $a$, the units digit of $a^{4}$ is $0, 1, ...$ "

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Math

Elementary Number Theory Problems 4.3 Solution (David M. Burton's 7th Edition) - Q1 Members Public

My Solution for "Use the binary exponentiation algorithm to compute both $19^{53} \pmod {503}$ and $141^{47} \pmod {1537}$. "

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Math

Basic Techniques for Solving Theory of Congruence Problems - 1 Members Public

8 Basic Techniques for solving theory of congruence/Modular Arithmetic problems summarised from my solution on Chapter 4.2 Elementary Number Theory 7th Edition Problems (David M. Burton).

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Math

Elementary Number Theory Problems 4.2 Solution (David M. Burton's 7th Edition) Members Public

My solutions for Burton's Elementary Number Theory Problems 4.2 (7th Edition)

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Math

Elementary Number Theory Problems 4.2 Solution (David M. Burton's 7th Edition) - Q18 Members Public

My Solution for "If $a \equiv b \pmod {n_{1}}$ and $a \equiv c \pmod {n2}$, prove that $b \equiv c \pmod {n}$, where the integer $n = gcd(n_{1}, n_{2})$."

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Math

Elementary Number Theory Problems 4.2 Solution (David M. Burton's 7th Edition) - Q17 Members Public

My Solution for "Prove that whenever $ab \equiv cd \pmod {n}$ and $b \equiv d \pmod {n}$, with $gcd(b, n) = 1$, then $a \equiv c \pmod {n}$."

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Ran
Math

Elementary Number Theory Problems 4.2 Solution (David M. Burton's 7th Edition) - Q16 Members Public

My Solution for "Use the theory of congruences to verify that $$89 \mid 2^{44} - 1 \qquad \text{and} \qquad 97 \mid 2 ^{48} - 1$$"

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Math

Elementary Number Theory Problems 4.2 Solution (David M. Burton's 7th Edition) - Q15 Members Public

My Solution for "Establish that if $a$ is an odd integer, then for any $n \geq 1$$$a^{2^{n}} \equiv 1 \pmod {2^{n + 2}}$$ [Hint: Proceed by induction on $n$.]"

Ran
Ran
Math